1/9/2024 0 Comments Null vector exampleJust point out one interesting thing right here. Of the vector 1, minus 2,ġ, 0, and the vector 2, minus 3, 0, 1. What do we call all the linearĬombinations of two vectors? It's the span of those Linear combinations of this vector and that vector. X's that satisfy this equation, it equals all of the Just a solution set of this equation, it's just all the Saying a linear combination of two vectors? Let me write this. That are a member of- We can pick any real number for x3Īnd we could pick any real number for x4. Two vectors, right? These are just random scalars Linear combination of these two vectors, of those Original equation, ax is equal to 0, can be represented as a These are a member R4, which satisfy the equation, our And what's x4 equal to? It's equal to 0 times To 1 times x3, plus 0 times x4, right? x3 is equal to x3. So then what is x3 equal to? Well, it's just equal In the problem, I'm making these silly mistakes. This x2 right here is x2 plusĢx3 plus 3x4 is equal to 0. What am I doing? I'm losing track of things. what's x1 equal to? It's equal to x3 timesġ plus x4 times 2. Of this, I could write x1, x2, x3, x4 is equal to Solution set to this equation, if I wanted to write it in terms I can solve this for x1 andĪ mistake here. Is equal to 0, and this obviously gives me no Here, there's no x1, you just have an x2, plus 2x3, plus 3x2 X3 minus x4, right? The 0 x2's is equal to 0. Here, this can be written as a system equations of x1 minus Has been reduced, just by doing reduce row echelonįorm, this problem. Row with the last row minus the middle row. It with the first row minus the second row, so IĬan get rid of this 1. Really just a little bit of an exercise just to Side of it, although these 0's are never going to change, it's Want to put this in reduced row echelon form, I want Guy with 4 times this guy, minus this guy. This 1 right here, so let me replace row 2 with rowĢ minus row 1. Row echelon form, were actually just putting matrix A Multiply or subtract by, you're just doing it all timesĠ, so you just keep ending up with 0. Not going to change at all, because no matter what you When you put it into row echelon form, this right side's And to solve this, and we'veĭone this before, we're just going to put this augmented There, that's just the 0 vector right there. We're going back to the augmented matrix world. This to equal that, and we wrote this as a system ofĮquations, but now we want to solve the system of equations, Should notice is we took the pain of multiplying this times I can represent this problemĪs the augmented matrix. We can represent this by anĪugmented matrix and then put that in reduced rowĮchelon form. Solution set to systems of equations like this. Solution set to this and we'll essentially have figured Vector with this column vector should be equal to that 0. Times this vector should be equal to that 0. Plus 2 times x2, plus 3 times x3, plus 4 times x4 is going And then this times this shouldīe equal to that 0. Plus 1 times x3, plus 1 times x4 is equal to this 0 there. The matrix multiplication, we get 1 times x1. So how do we do this? Well, this is just a straight Of these vectors is equal to the 0 vector. This particular A, such that my matrix A times any Vectors that are going to be members of R4, because I'm using Rn, but this is a 3 by 4 matrix, so these are all the Of all vectors that are a member of - we generally say Of all of these x's that satisfy this? Let me just write ourįormal notation. So I should have three 0's So myĠ vector is going to be the 0 vector in R3. Row times, that's the second entry, and then the third row. This and that's going to be the first entry, then this And what am I going to get? I'm going to have one row times The null space is the set ofĪll the vectors, and when I multiply it times A, I Only legitimately defined multiplication of this times aįour-component vector or a member of Rn. Times this vector I should get the 0 vector. X1, x2, x3, x4 is a member of our null space. Times any of those vectors, so let me say that the vector Just the set of all the vectors that, when I multiply A ![]() ![]() But in this video let's actuallyĬalculate the null space for a matrix. Somewhat theoretically about what a null space isĪnd we showed that it is a valid subspace.
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